Files
ohm_streaming/app/downloaders/video_players/uqload.py
root 4d280b5239 docs: Update CLAUDE.md with three-tier architecture and new providers
- Added new video players: Vidzy, LuLuvid, Uqload
- Added new anime site: French-Manga
- Added new series sites category with FS7
- Updated documentation to reflect three-tier architecture (anime sites → series sites → video players)
- Added BaseSeriesSite interface documentation
- Added "Adding New Series Site" section
- Updated test organization with test_french_manga.py

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Co-Authored-By: Claude <noreply@anthropic.com>
Co-Authored-By: Happy <yesreply@happy.engineering>
2026-01-25 10:34:39 +00:00

111 lines
4.1 KiB
Python

"""Uqload video hosting service downloader"""
import logging
import re
from typing import Optional
from .base import BaseVideoPlayer
from bs4 import BeautifulSoup
from app.utils import sanitize_filename
logger = logging.getLogger(__name__)
class UqloadDownloader(BaseVideoPlayer):
"""
Downloader for Uqload video hosting service.
Uqload is a video hosting platform used by French Stream and other streaming sites.
"""
def can_handle(self, url: str) -> bool:
"""Check if this downloader can handle the given URL"""
return "uqload" in url.lower()
async def get_download_link(
self,
url: str,
target_filename: Optional[str] = None
) -> tuple[str, str]:
"""
Extract direct download link and filename from Uqload URL.
Args:
url: The Uqload video player URL
target_filename: Optional filename override
Returns:
Tuple of (download_url, filename)
"""
try:
logger.info(f"Fetching Uqload URL: {url}")
# Fetch the page
response = await self.client.get(url)
response.raise_for_status()
html = response.text
# Method 1: Look for video URL in JavaScript
# Uqload stores the video URL in a JavaScript variable like: sources: ["URL"]
patterns = [
r'sources:\s*\["([^"]+\.mp4[^"]*)"\]',
r'sources:\s*\[["\']([^"\']+\.mp4[^"\']*)["\']\]',
r'"sources":\s*\["([^"]+\.mp4[^"]*)"\]',
r'file:\s*"([^"]+\.mp4[^"]*)"',
r'file:\s*["\']([^"\']+\.mp4[^"\']*)["\']',
r'"file"\s*:\s*"([^"]+\.mp4[^"]*)"',
]
for pattern in patterns:
match = re.search(pattern, html)
if match:
download_url = match.group(1)
# Clean up any escape characters
download_url = download_url.replace('\\/', '/')
logger.info(f"Found video source from JavaScript pattern: {pattern[:20]}...")
break
else:
# Method 2: Try parsing with BeautifulSoup
soup = BeautifulSoup(html, 'lxml')
# Look for video tag
video_tag = soup.find('video')
if video_tag and video_tag.get('src'):
download_url = video_tag['src']
logger.info(f"Found video source from <video> tag")
else:
# Look for source tag
source_tag = soup.find('source')
if source_tag and source_tag.get('src'):
download_url = source_tag['src']
logger.info(f"Found video source from <source> tag")
else:
raise ValueError("Could not find video URL in Uqload page")
# Ensure URL is absolute
if not download_url.startswith('http'):
if download_url.startswith('//'):
download_url = 'https:' + download_url
else:
from urllib.parse import urljoin
download_url = urljoin(url, download_url)
# Generate filename
if target_filename:
filename = sanitize_filename(target_filename)
else:
# Try to extract filename from URL
filename = download_url.split('/')[-1].split('?')[0]
if not filename or len(filename) < 5:
filename = "uqload_video.mp4"
filename = sanitize_filename(filename)
# Ensure .mp4 extension
if not filename.endswith('.mp4'):
filename += '.mp4'
logger.info(f"Successfully extracted Uqload download link: {filename}")
return download_url, filename
except Exception as e:
logger.error(f"Error extracting Uqload download link: {e}")
raise ValueError(f"Failed to extract download link from Uqload: {str(e)}")